Question

use ohms law to answer the following questions: 1. a 9v battery is connected to a circuit with a 470 - ohm resistor. how much current (in amps) is flowing through the circuit? 2. if you have a current of 0.02 amps flowing through an led, and the resistance is 330 ohms, what is the voltage across the resistor?

Explanation:

Step1: Recall Ohm's Law formula

Ohm's Law is $V = IR$, where $V$ is voltage, $I$ is current and $R$ is resistance. For the first - question, we need to find $I$, so we can rewrite the formula as $I=\frac{V}{R}$.

Step2: Calculate current for the first question

Given $V = 9V$ and $R = 470\Omega$, then $I=\frac{9}{470}\approx0.0191A$.

Step3: For the second question, use the original Ohm's Law formula

We know $I = 0.02A$ and $R = 330\Omega$. Using $V = IR$, we substitute the values.

Step4: Calculate voltage for the second question

$V=0.02\times330 = 6.6V$.

Answer:

1. Approximately $0.0191$ amps
2. $6.6$ volts