Question

use for questions 1-3: the weights of dogs in a d and a standard deviation of 17.2 pounds. use a s

1. p(z < -0.8)

0.211 86(100)=21.58c - 1.

Explanation:

Step1: Use z - table lookup

We use the standard normal distribution z - table. The z - table gives the cumulative probability $P(Z < z)$ for a standard normal random variable $Z$.

Step2: Find the value

Looking up $z=-0.8$ in the standard normal distribution table, we find that $P(Z < - 0.8)=0.2119$.

Answer:

$0.2119$