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use the table below to answer the next three questions. (q.15 - q.16 - …

Question

use the table below to answer the next three questions. (q.15 - q.16 - q.17)

mercurycoppersilvergold

q.16. what is the volume of a copper wire that has a mass of 1335 grams?
a) 150 cm³ b) 200 cm³ c) 250 cm³ d) 300 cm³

q.17. what is the mass of a gold ring that has a volume of 50 cm³?
a) 445 grams b) 525 grams c) 675 grams d) 965 grams

Explanation:

Response
Q.16

Step1: Recall density formula

Density formula is $
ho = \frac{m}{V}$, so we can rearrange it to find volume: $V = \frac{m}{
ho}$.

Step2: Identify values

Mass of copper wire $m = 1335$ grams, density of copper $
ho = 8.9$ g/cm³.

Step3: Calculate volume

Substitute values into the formula: $V = \frac{1335}{8.9} = 150$ cm³.

Step1: Recall density formula

Density formula is $
ho = \frac{m}{V}$, so we can rearrange it to find mass: $m =
ho \times V$.

Step2: Identify values

Volume of gold ring $V = 50$ cm³, density of gold $
ho = 19.3$ g/cm³.

Step3: Calculate mass

Substitute values into the formula: $m = 19.3 \times 50 = 965$ grams. Wait, no, wait, 19.350: 1950=950, 0.350=15, so 950+15=965? Wait, but let me check again. Wait, the options for Q.17: d) 965 grams. Wait, but wait, maybe I made a mistake? Wait, no, 19.3 50: 19.350 = (20 - 0.7)50 = 1000 - 35 = 965. Yes. So the mass is 965 grams.

Answer:

a) 150 cm³

Q.17