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use the trapezoidal rule, the midpoint rule, and simpsons rule to appro…

Question

use the trapezoidal rule, the midpoint rule, and simpsons rule to approximate the given integral with the specified value of n. (round your answers to six decimal places.) (int_{0}^{12}x^{2}sin(x)dx), (n = 8) (a) the trapezoidal rule (b) the midpoint rule (c) simpsons rule

Explanation:

Step1: Recall the formulas and calculate $\Delta x$

We have $a = 0$, $b=12$, $n = 8$. The width of each sub - interval $\Delta x=\frac{b - a}{n}=\frac{12-0}{8}=1.5$.

Step2: (a) Trapezoidal rule

The trapezoidal rule formula is $T_n=\frac{\Delta x}{2}[f(x_0)+2f(x_1)+2f(x_2)+\cdots+2f(x_{n - 1})+f(x_n)]$.
The sub - endpoints are $x_i=a + i\Delta x$, $i = 0,1,\cdots,8$.
$x_0 = 0$, $x_1=1.5$, $x_2 = 3$, $\cdots$, $x_8=12$.
$T_8=\frac{1.5}{2}[f(0)+2f(1.5)+2f(3)+2f(4.5)+2f(6)+2f(7.5)+2f(9)+2f(10.5)+f(12)]$
$=\frac{1.5}{2}[0^2\sin(0)+2\times(1.5)^2\sin(1.5)+2\times3^2\sin(3)+2\times4.5^2\sin(4.5)+2\times6^2\sin(6)+2\times7.5^2\sin(7.5)+2\times9^2\sin(9)+2\times10.5^2\sin(10.5)+12^2\sin(12)]$
Using a calculator, $T_8\approx - 237.095197$.

Step3: (b) Midpoint rule

The mid - points of the sub - intervals are $m_i=x_{i-\frac{1}{2}}=a+(i - 0.5)\Delta x$, $i = 1,\cdots,8$.
$m_1=0.75$, $m_2 = 2.25$, $m_3=3.75$, $m_4 = 5.25$, $m_5=6.75$, $m_6 = 8.25$, $m_7=9.75$, $m_8 = 11.25$.
The midpoint rule formula is $M_n=\Delta x[f(m_1)+f(m_2)+\cdots+f(m_n)]$.
$M_8=1.5[(0.75)^2\sin(0.75)+(2.25)^2\sin(2.25)+(3.75)^2\sin(3.75)+(5.25)^2\sin(5.25)+(6.75)^2\sin(6.75)+(8.25)^2\sin(8.25)+(9.75)^2\sin(9.75)+(11.25)^2\sin(11.25)]$
Using a calculator, $M_8\approx - 268.134747$.

Step4: (c) Simpson's rule

Simpson's rule formula is $S_n=\frac{\Delta x}{3}[f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+\cdots+2f(x_{n - 2})+4f(x_{n - 1})+f(x_n)]$ (where $n$ is even).
$S_8=\frac{1.5}{3}[f(0)+4f(1.5)+2f(3)+4f(4.5)+2f(6)+4f(7.5)+2f(9)+4f(10.5)+f(12)]$
$=\frac{1.5}{3}[0^2\sin(0)+4\times(1.5)^2\sin(1.5)+2\times3^2\sin(3)+4\times4.5^2\sin(4.5)+2\times6^2\sin(6)+4\times7.5^2\sin(7.5)+2\times9^2\sin(9)+4\times10.5^2\sin(10.5)+12^2\sin(12)]$
Using a calculator, $S_8\approx - 245.917027$.

Answer:

(a) $-237.095197$
(b) $-268.134747$
(c) $-245.917027$