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using the graphing calculator to include a solution mr. hernandez plott…

Question

using the graphing calculator to include a solution mr. hernandez plotted the point (1, 1) on hans graph of $yleq\frac{1}{2}x + 2$. he instructed han to add a second inequality to the graph that would include the solution (1, 1). which equation could miguel write? $y>2x + 1$ $y<2x - 1$ $ygeq2x + 1$ $yleq2x - 1$

Explanation:

Step1: Substitute x = 1 and y = 1 into each inequality

For $y>2x + 1$, when $x = 1$, $2x+1=2\times1 + 1=3$, and $1
gtr3$.
For $y<2x - 1$, when $x = 1$, $2x - 1=2\times1-1 = 1$, and $1
less1$.
For $y\geq2x + 1$, when $x = 1$, $2x + 1=3$, and $1
geq3$.
For $y\leq2x - 1$, when $x = 1$, $2x - 1=1$, and $1\leq1$ which is True.

Answer:

$y\leq2x - 1$