Question

1. the variance of a distribution is 195. what is the standard deviation, rounded to the nearest thousandth?

Explanation:

Step1: Recall the relationship

The standard deviation $\sigma$ is the square - root of the variance $\sigma^{2}$. Given $\sigma^{2}=195$.
$\sigma=\sqrt{\sigma^{2}}=\sqrt{195}$

Step2: Calculate the value

Using a calculator, $\sqrt{195}\approx13.96424$.
Rounding to the nearest thousandth, we get $\sigma\approx13.964$.

Answer:

$13.964$