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Question
- the vertices of a triangle are as follows: (6,-3), (1,5), and (8,-4) if you dilate the triangle by a scale factor of 3, what are the vertices of the new triangle? (9,-6),(4,2),(11,-7) (9,0),(4,8),(11,-1) (18,-9),(3,15),(24,-12) (3,-6),(-2,2),(5,-7)
Step1: Recall dilation rule
To dilate a point $(x,y)$ by a scale factor $k$, we use the rule $(x,y)\to(kx,ky)$.
Step2: Dilate first - point
For the point $(6, - 3)$ with $k = 3$, we have $(3\times6,3\times(-3))=(18,-9)$.
Step3: Dilate second - point
For the point $(1,5)$ with $k = 3$, we have $(3\times1,3\times5)=(3,15)$.
Step4: Dilate third - point
For the point $(8,-4)$ with $k = 3$, we have $(3\times8,3\times(-4))=(24,-12)$.
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C. $(18,-9),(3,15),(24,-12)$