Question

the water level was originally at 18 ml. after putting a metal object inside, the water rose to 36 ml.
a) how much did the water level rise? show your work.
b) what is the volume of the object?
3.
amir measured 3.0 l of lemonade into the pitcher. he put 8 equal-sized ice cubes inside.
the liquid rose to 3.4 l.
what is the volume of each ice cube? show your work.

1. convert the following:

a) $36\\ \text{m}^3 = \underline{\quad\quad\quad\quad\quad\quad\quad\quad}\\ \text{cm}^3$
b) $5,600\\ \text{cm}^2 = \underline{\quad\quad\quad\quad\quad\quad\quad\quad}\\ \text{m}^2$
c) $1.5\\ \text{km}^2 = \underline{\quad\quad\quad\quad\quad\quad\quad\quad}\\ \text{m}^2$

Explanation:

Step1: Calculate water level rise

$36\ \text{mL} - 18\ \text{mL} = 18\ \text{mL}$

Step2: Find object's volume

Volume = water rise = $18\ \text{mL}$

Step3: Total ice volume (problem 3)

$3.4\ \text{L} - 3.0\ \text{L} = 0.4\ \text{L}$

Step4: Volume per ice cube

$\frac{0.4\ \text{L}}{8} = 0.05\ \text{L}$

Step5: Convert $36\ \text{m}^3$ to $\text{cm}^3$

$36 \times 10^6\ \text{cm}^3 = 36000000\ \text{cm}^3$

Step6: Convert $5600\ \text{cm}^2$ to $\text{m}^2$

$5600 \times 10^{-4}\ \text{m}^2 = 0.56\ \text{m}^2$

Step7: Convert $1.5\ \text{km}^2$ to $\text{m}^2$

$1.5 \times 10^6\ \text{m}^2 = 1500000\ \text{m}^2$

Answer:

a) $18\ \text{mL}$
b) $18\ \text{mL}$

1. $0.05\ \text{L}$
2. a) $36000000$

b) $0.56$
c) $1500000$