Question

wc math 20-2 / assess / m1l2 sine law m1l2 sine law back question 3 not yet answered marked out of 2 flag question solve for the unknown angle measure. round your answer to the nearest degree. $\frac{15.2}{sin h}=\frac{12.0}{sin 50^{circ}}$ select one: a. $77^{circ}$ b. $74^{circ}$ c. $76^{circ}$ d. $75^{circ}$

Explanation:

Step1: Cross - multiply

$15.2\times\sin50^{\circ}=12.0\times\sin H$

Step2: Calculate $15.2\times\sin50^{\circ}$

$15.2\times\sin50^{\circ}\approx15.2\times0.766 = 11.6432$
So, $11.6432 = 12.0\times\sin H$

Step3: Solve for $\sin H$

$\sin H=\frac{11.6432}{12.0}\approx0.9703$

Step4: Find the angle $H$

$H=\sin^{- 1}(0.9703)\approx76^{\circ}$

Answer:

C. $76^{\circ}$