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what is the approximate value of y - x? 4.9° 6.2° 11.1° 17.2°

Question

what is the approximate value of y - x?
4.9°
6.2°
11.1°
17.2°

Explanation:

Step1: Find $\tan x$ and $\tan y$

In right - triangle $LMN$, $\tan x=\frac{14.1}{19.1}$ and $\tan y = \frac{19.1}{14.1}$.

Step2: Calculate $x$ and $y$

$x=\arctan(\frac{14.1}{19.1})\approx36.3^{\circ}$, $y=\arctan(\frac{19.1}{14.1})\approx53.5^{\circ}$.

Step3: Calculate $y - x$

$y - x\approx53.5^{\circ}-36.3^{\circ}=17.2^{\circ}$.

Answer:

$17.2^{\circ}$