Question

what is the center of the circle with the equation $(x + 6)^{2}+(y - 5)^{2}=100$?
a. $(6,-5)$
b. $(-6,5)$
c. $(6,5)$
d. $(-6,-5)$

Explanation:

Step1: Recall circle - equation form

The standard form of a circle equation is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center of the circle.

Step2: Rewrite the given equation

The given equation is $(x + 6)^2+(y - 5)^2=100$, which can be rewritten as $(x-(-6))^2+(y - 5)^2 = 10^2$.

Answer:

B. $(-6,5)$