Question

what is the change in heat of a 5.57 - kilogram block of aluminum when its temperature increases from - 28°c to - 19°c? the specific heat of aluminum is 0.897 j/g°c. round your answer to the correct number of significant figures. joules complete the sentence. this process is because heat is by the aluminum.

Explanation:

Step1: Convert mass to grams

$m = 5.57\ kg\times1000\ g/kg= 5570\ g$

Step2: Calculate temperature change

$\Delta T=T_2 - T_1=- 19^{\circ}C-(-28^{\circ}C)=9^{\circ}C$

Step3: Use heat - change formula

$Q = mc\Delta T$, where $c = 0.897\ J/g^{\circ}C$, $m = 5570\ g$, $\Delta T=9^{\circ}C$
$Q=5570\ g\times0.897\ J/g^{\circ}C\times9^{\circ}C$
$Q = 5570\times0.897\times9\ J$
$Q=44939.61\ J\approx4.49\times 10^{4}\ J$

Step4: Determine heat - transfer nature

The process is endothermic because heat is absorbed by the aluminum.

Answer:

$4.49\times 10^{4}$ joules
This process is endothermic because heat is absorbed by the aluminum.