Question

what is the change in velocity of a 1323 kg truck that experiences an impulse of 301 n - s? include 2 decimal places in your answer.

Explanation:

Step1: Recall impulse - momentum theorem

Impulse $J = \Delta p$, and $\Delta p=m\Delta v$. So $\Delta v=\frac{J}{m}$.

Step2: Substitute given values

Given $J = 301\ N\cdot s$ and $m = 1323\ kg$. Then $\Delta v=\frac{301}{1323}$.

Step3: Calculate the result

$\Delta v\approx0.23\ m/s$

Answer:

$0.23$