Question

1. what is the current in a 160v circuit if the resistance is 20ω? v= i= r= 3. what is the current in a 160v circuit if the resistance is 10ω? v= i= r= 4. what is the current in a 160v circuit if the resistance is 5ω? v= i= r= 5. based on questions 2, 3, and 4, what happens to the current in a circuit as the resistance decreases? increases? 6. what voltage is required to move 6a through 5ω? v= i= r= 7. what voltage is required to move 6a through 10ω? v= i= r= 8. what voltage is required to move 6a through 20ω? v= i= r= 9. based on questions 6, 7, and 8, what happens to the voltage required in a circuit as the resistance decreases? increases?

Explanation:

Step1: Recall Ohm's law

Ohm's law is $V = IR$, where $V$ is voltage, $I$ is current and $R$ is resistance. We can rewrite it as $I=\frac{V}{R}$ and $V = IR$ for different - type of calculations.

Step2: Solve question 2

Given $V = 160V$ and $R=20\Omega$. Using $I=\frac{V}{R}$, we have $I=\frac{160}{20}=8A$.

Step3: Solve question 3

Given $V = 160V$ and $R = 10\Omega$. Using $I=\frac{V}{R}$, we get $I=\frac{160}{10}=16A$.

Step4: Solve question 4

Given $V = 160V$ and $R = 5\Omega$. Using $I=\frac{V}{R}$, we obtain $I=\frac{160}{5}=32A$.

Step5: Answer question 5

As the resistance $R$ decreases while the voltage $V$ is constant, according to $I=\frac{V}{R}$, the current $I$ increases.

Step6: Solve question 6

Given $I = 6A$ and $R = 5\Omega$. Using $V=IR$, we have $V=6\times5 = 30V$.

Step7: Solve question 7

Given $I = 6A$ and $R = 10\Omega$. Using $V=IR$, we get $V=6\times10=60V$.

Step8: Solve question 8

Given $I = 6A$ and $R = 20\Omega$. Using $V=IR$, we obtain $V=6\times20 = 120V$.

Step9: Answer question 9

As the resistance $R$ increases while the current $I$ is constant, according to $V = IR$, the voltage $V$ increases.

Answer:

1. $V = 160V$, $I = 8A$, $R = 20\Omega$
2. $V = 160V$, $I = 16A$, $R = 10\Omega$
3. $V = 160V$, $I = 32A$, $R = 5\Omega$
4. As the resistance decreases, the current increases.
5. $V = 30V$, $I = 6A$, $R = 5\Omega$
6. $V = 60V$, $I = 6A$, $R = 10\Omega$
7. $V = 120V$, $I = 6A$, $R = 20\Omega$
8. As the resistance increases, the voltage required increases.