Question

2 what is the frequency of electromagnetic radiation with a wavelength of 3.33 x 10^-8 m? * (0.5 points) 4.54 x 10^12 hz 1.98 x 10^4 hz 9.01 x 10^-1 hz 9.01 x 10^15 hz 9.99 hz 1.11 x 10^-16 hz

Explanation:

Step1: Recall the speed - wavelength - frequency formula

The speed of light $c$ is related to wavelength $\lambda$ and frequency $
u$ by the formula $c = \lambda
u$, where $c = 3\times10^{8}\ m/s$. We need to solve for $
u$, so $
u=\frac{c}{\lambda}$.

Step2: Substitute the given values

Given $\lambda = 3.33\times 10^{-8}\ m$ and $c = 3\times10^{8}\ m/s$. Then $
u=\frac{3\times 10^{8}}{3.33\times 10^{-8}}$.
Using the rule of exponents $\frac{a^{m}}{a^{n}}=a^{m - n}$, we have $
u=\frac{3}{3.33}\times10^{8-(- 8)}=\frac{3}{3.33}\times10^{16}$.
$\frac{3}{3.33}\approx0.901$, so $
u = 9.01\times 10^{15}\ Hz$.

Answer:

$9.01\times 10^{15}\ Hz$