Question

1. what is $4\frac{4}{8}-\frac{7}{8}$?

a. $3\frac{3}{8}$
b. $3\frac{5}{8}$
c. $4\frac{3}{8}$
d. $5\frac{1}{8}$

1. marci had $1\frac{3}{4}$ feet of ribbon for a project. she bought $\frac{3}{4}$ foot of ribbon to finish.

how many feet of ribbon did marci use for her project?
a. $\frac{1}{2}$
b. $2\frac{1}{4}$
c. $2\frac{1}{2}$
d. $2\frac{2}{3}$

1. mary bought 2 chickens at the grocery store. one chicken weighed $2\frac{3}{4}$ pounds and the other chicken weighed $3\frac{3}{4}$ pounds. how many pounds of chicken did mary buy?

a. 1 pound
b. $5\frac{6}{4}$ pounds
c. $6\frac{1}{2}$ pounds
d. $7\frac{6}{4}$ pounds

Explanation:

(Question 7):

Step1: Convert mixed number to improper fraction

$4\frac{4}{8} = \frac{4\times8 + 4}{8} = \frac{36}{8}$

Step2: Subtract the fractions

$\frac{36}{8} - \frac{7}{8} = \frac{36-7}{8} = \frac{29}{8}$

Step3: Convert back to mixed number

$\frac{29}{8} = 3\frac{5}{8}$

(Question 8):

Step1: Add the two ribbon lengths

$1\frac{3}{4} + \frac{3}{4} = \frac{7}{4} + \frac{3}{4}$

Step2: Calculate the sum

$\frac{7+3}{4} = \frac{10}{4} = 2\frac{1}{2}$

(Question 9):

Step1: Add the two chicken weights

$2\frac{3}{4} + 3\frac{3}{4} = \frac{11}{4} + \frac{15}{4}$

Step2: Calculate the sum

$\frac{11+15}{4} = \frac{26}{4} = 6\frac{1}{2}$

Answer:

1. B. $3\frac{5}{8}$
2. C. $2\frac{1}{2}$
3. C. $6\frac{1}{2}$ pounds