Question

what is the measure of each interior angle of a regular pentagon? enter your answer in the box.

Explanation:

Step1: Recall angle - sum formula

The sum of interior angles of a polygon is $(n - 2)\times180^{\circ}$, where $n$ is the number of sides. For a pentagon, $n = 5$. So the sum is $(5 - 2)\times180^{\circ}=540^{\circ}$.

Step2: Calculate each interior angle

Since it's a regular pentagon, all interior angles are equal. So each interior angle is $\frac{540^{\circ}}{5}=108^{\circ}$.

Answer:

$108$