Question

1. what is the midpoint m given s(-8, -6) and t(4, 12)? (-2, 3) (-1, -4) (7, 8) (-6, -9)

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $M(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Here $x_1=-8,y_1 = - 6,x_2 = 4,y_2=12$.

Step2: Calculate x - coordinate of mid - point

$x=\frac{-8 + 4}{2}=\frac{-4}{2}=-2$.

Step3: Calculate y - coordinate of mid - point

$y=\frac{-6+12}{2}=\frac{6}{2}=3$.

Answer:

A. (-2,3)