Question

what is the potential of a series circuit that has a current of 0.50 amps and three identical 3.0 ohm resistors? o 4.5 v o 1.5 v o 0.50 v o 9.5 v

Explanation:

Step1: Calculate total resistance

In a series - circuit, the total resistance $R_{total}$ is the sum of individual resistances. Given three identical resistors $R = 3.0\Omega$ each, $R_{total}=3\times3.0\Omega = 9.0\Omega$.

Step2: Use Ohm's law

Ohm's law is $V = IR$, where $V$ is potential difference, $I$ is current, and $R$ is resistance. Given $I = 0.50A$ and $R_{total}=9.0\Omega$, then $V=0.50A\times9.0\Omega = 4.5V$.

Answer:

$4.5V$