Question

1. what would be the product of ((3x + 0.5)(3x - 0.5))?

a. (9x^2 + 0.75)

b. (9x^2 - 1.5)

c. (9x^2 - 0.25)

d. (9x^2 + 0.25)

Explanation:

Step1: Recognize difference of squares

The expression $(a+b)(a-b)=a^2-b^2$, where $a=3x$, $b=0.5$.

Step2: Calculate $a^2$

$a^2=(3x)^2=9x^2$

Step3: Calculate $b^2$

$b^2=(0.5)^2=0.25$

Step4: Substitute into formula

$(3x+0.5)(3x-0.5)=9x^2 - 0.25$

Answer:

c. $9x^2 - 0.25$