Question

what is $x^2 - 6 = 16x + 30$ rewritten in standard form, then factored? (x - 18)(x + 2) = 0 (x - 6)(x - 6) = 0 (x + 6)(x - 6) = 0 (x + 18)(x - 2) = 0 e the equation true?

Explanation:

Step1: Move all terms to left side

$x^2 - 6 - 16x - 30 = 0$

Step2: Combine like terms

$x^2 - 16x - 36 = 0$

Step3: Factor the quadratic

Find two numbers that multiply to $-36$ and add to $-16$: $-18$ and $2$.
$(x - 18)(x + 2) = 0$

Answer:

$(x - 18)(x + 2) = 0$