Question

what is the solution of 3 + \frac{x - 3}{2}\leq4? x\geq3 x\leq3 x < 3 x > 3 -calculus cp ic 25 - 26 al inequalities

Explanation:

Step1: Isolate the variable terms

First, start with the inequality $3+\frac{x - 2}{2}\leq4$. Subtract 3 from both sides: $\frac{x - 2}{2}\leq4 - 3$, so $\frac{x - 2}{2}\leq1$.

Step2: Eliminate the fraction

Multiply both sides of the inequality by 2 to get $x - 2\leq2$.

Step3: Solve for x

Add 2 to both sides of the inequality: $x\leq2 + 2$, so $x\leq4$.

Answer:

The solution of the inequality is $x\leq4$.