Question

what is the solution to this equation?
$5x + 15 + 2x = 24 + 4x$
a. $x = \frac{9}{11}$
b. $x = 3$
c. $x = 13$
d. $x = \frac{39}{11}$

Explanation:

Step1: Combine like terms on left side

Combine \(5x\) and \(2x\) to get \(7x\), so the equation becomes \(7x + 15 = 24 + 4x\).

Step2: Subtract \(4x\) from both sides

Subtracting \(4x\) from both sides gives \(7x - 4x + 15 = 24 + 4x - 4x\), which simplifies to \(3x + 15 = 24\).

Step3: Subtract 15 from both sides

Subtracting 15 from both sides: \(3x + 15 - 15 = 24 - 15\), so \(3x = 9\).

Step4: Divide both sides by 3

Dividing both sides by 3: \(\frac{3x}{3} = \frac{9}{3}\), which gives \(x = 3\).

Answer:

B. \(x = 3\)