Question

what is the solution to the inequality $4x - 1 \leq 11$?
\\(\circ\\) a. $x \leq 2.5$
\\(\circ\\) b. $x \geq 3$
\\(\circ\\) c. $x \geq 2.5$
\\(\circ\\) d. $x \leq 3$

Explanation:

Step1: Add 1 to both sides

\(4x - 1 + 1 \leq 11 + 1\)
\(4x \leq 12\)

Step2: Divide both sides by 4

\(\frac{4x}{4} \leq \frac{12}{4}\)
\(x \leq 3\)

Answer:

d. \(x \leq 3\)