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Question
what is the sum of the exterior angle measures, one at each vertex, of a triangle?
Step1: Recall the exterior angle theorem for polygons
For any polygon, the sum of the exterior angles (one at each vertex) is always \(360^\circ\) when considering convex polygons. A triangle is a convex polygon (in the standard case we consider for basic geometry).
Step2: Apply the theorem to a triangle
Since a triangle is a polygon with three sides, using the general result for the sum of exterior angles of a polygon, the sum of the exterior angle measures (one at each vertex) of a triangle is \(360^\circ\).
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\(360^\circ\)