Question

what three numbers are the pythagorean triple generated by using 4 for x and 1 for y. remember to use the formulas: $a = x^{2}-y^{2}, b = 2xy, c = x^{2}+y^{2}$

a. 3,5 and 8
b. 5,11 and 12
c. 8,15 and 17
d. 6,8 and 10

Explanation:

Step1: Calculate the value of a

Substitute $x = 4$ and $y = 1$ into $a=x^{2}-y^{2}$.
$a=4^{2}-1^{2}=16 - 1=15$

Step2: Calculate the value of b

Substitute $x = 4$ and $y = 1$ into $b = 2xy$.
$b=2\times4\times1=8$

Step3: Calculate the value of c

Substitute $x = 4$ and $y = 1$ into $c=x^{2}+y^{2}$.
$c=4^{2}+1^{2}=16 + 1=17$

Answer:

C. 8, 15 and 17