Question

1. what is the value of x for \\(\frac{x + 8}{3}=7\\) ?
2. what is the value of x for \\(\frac{x}{6}+ 3 = 15\\) ?

Explanation:

Question 9

Step1: Eliminate the denominator

Multiply both sides of the equation $\frac{x + 8}{3}=7$ by 3 to get rid of the denominator.
$$(x + 8)=\ 7\times3$$

Step2: Calculate the right - hand side

Calculate $7\times3 = 21$, so the equation becomes $x + 8=21$.

Step3: Solve for x

Subtract 8 from both sides of the equation $x + 8=21$.
$$x=21 - 8$$
$$x = 13$$

Step1: Isolate the fraction term

Subtract 3 from both sides of the equation $\frac{x}{6}+3 = 15$.
$$\frac{x}{6}=15 - 3$$

Step2: Calculate the right - hand side

Calculate $15 - 3=12$, so the equation becomes $\frac{x}{6}=12$.

Step3: Solve for x

Multiply both sides of the equation $\frac{x}{6}=12$ by 6.
$$x=12\times6$$
$$x = 72$$

Answer:

$x = 13$

Question 10