QUESTION IMAGE
Question
what is the value of a? 10a + 52° 12a a + 26° write your answer as an int a =
Step1: Apply exterior - angle theorem
The exterior - angle of a triangle is equal to the sum of the two non - adjacent interior angles. So, $10a + 52=(a + 26)+12a$.
Step2: Simplify the equation
First, expand the right - hand side: $10a+52=a + 26+12a$. Combine like terms: $10a+52 = 13a+26$.
Step3: Solve for a
Subtract $10a$ from both sides: $52=3a + 26$. Then subtract 26 from both sides: $3a=52 - 26=26$. Divide both sides by 3: $a=\frac{26}{3}\approx8.67$. But if we assume there is a mistake and it should be $10a+52=(a + 26)+12a$ simplified to $10a+52=13a + 26$, then moving terms around gives $13a-10a=52 - 26$, so $3a = 26$, and $a=\frac{26}{3}$. If we assume the correct equation based on the exterior - angle theorem and solve it correctly:
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Let's re - check our work. Substitute $a=\frac{26}{3}$ into the angle expressions. The exterior angle is $10\times\frac{26}{3}+52=\frac{260}{3}+52=\frac{260 + 156}{3}=\frac{416}{3}$. The sum of the non - adjacent interior angles is $(\frac{26}{3}+26)+12\times\frac{26}{3}=\frac{26+78}{3}+\frac{312}{3}=\frac{104 + 312}{3}=\frac{416}{3}$.
However, if we assume the equation was set up wrong and we should have $10a+52-(a + 26)=12a$ (a different interpretation of the relationship), then $10a+52 - a-26=12a$, $9a + 26=12a$, $12a-9a=26$, $3a=26$, $a=\frac{26}{3}$.
If we assume the correct application of the exterior - angle theorem for a triangle:
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If we assume the correct geometric relationship and solve step - by - step:
Step1: Set up the equation using exterior angle theorem
The exterior angle $10a + 52$ is equal to the sum of the two non - adjacent interior angles $a + 26$ and $12a$. So, $10a+52=(a + 26)+12a$.
Step2: Combine like terms
$10a+52=13a + 26$.
Step3: Isolate the variable a
Subtract $10a$ from both sides: $52 = 3a+26$. Then subtract 26 from both sides: $3a=26$. So, $a=\frac{26}{3}$.
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$a=\frac{26}{3}$