Question

(where is is labeled \t\) f₁ 2.00 kg t 1.00 kg 9.8 n 0.31 n 1 n 29.4 n clear all

Explanation:

Step1: Analyze forces on 1.00 - kg mass

The force of gravity on the 1.00 - kg mass is given by $F = mg$, where $m = 1.00\ kg$ and $g=9.8\ m/s^{2}$.
$F = 1.00\times9.8=9.8\ N$. In the vertical - direction, for the 1.00 - kg mass at rest (assuming the system is in equilibrium or at constant velocity), the tension $T$ in the string is equal to the force of gravity acting on it. According to Newton's second law $F_{net}=ma$, and when $a = 0$, $T - mg=0$, so $T=mg$.

Step2: Calculate tension value

Substitute $m = 1.00\ kg$ and $g = 9.8\ m/s^{2}$ into the formula $T=mg$.
$T=1.00\times9.8 = 9.8\ N$

Answer:

$9.8\ N$