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which parallelogram is divided into two triangles that can be proven co…

Question

which parallelogram is divided into two triangles that can be proven congruent by sss? (1 point) abcd jklm pqrs wxyz

Explanation:

Step1: Recall SSS congruence

SSS (Side - Side - Side) congruence means all three sides of one triangle are equal to the corresponding three sides of another triangle.

Step2: Analyze parallelograms

In parallelogram \(WXYZ\), the diagonal divides it into two triangles where the sides of the triangles formed are equal due to the properties of a parallelogram (opposite sides of a parallelogram are equal) and the common diagonal. The markings on the sides of the triangles in parallelogram \(WXYZ\) show that all three pairs of corresponding sides are congruent. In \(ABCD\) and \(JKLM\) we have angle - markings which are not relevant for SSS, and in \(PQRS\) the markings do not show all three - side equalities for the two triangles formed by the diagonal.

Answer:

WXYZ