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Question
which pieces of information can be gathered from these histograms? choose all answers that apply: a it was warmer in minneapolis every day. b minneapolis had the coldest daily high temperature of these two cities. c none of the above
Brief Explanations
- Option A: The histogram doesn't provide daily temperature comparisons for each day, so we can't conclude it was warmer in Minneapolis every day.
- Option B: From the histogram (assuming one city has a lower temperature range, and Minneapolis is part of that), if Minneapolis has the coldest daily high temperature among the two cities (as per the histogram's temperature bins, e.g., the left - most bin with lower temperature is associated with Minneapolis), then this can be inferred. Wait, actually, looking at the histogram (even with the partial view), the first bin (15 - 18) is for one city, and the later bins (21 +) for another. If Minneapolis is in the lower - temperature bin city, then it has the coldest daily high (since its highest temperature bin is lower than the other city's lowest). But actually, re - evaluating: The problem's histogram (even with the given part) – if we assume two cities, one with temperatures in 15 - 18 and another in 21+, then Minneapolis (if in the 15 - 18 group) has the coldest daily high. But wait, the original problem's options: Let's re - check. Option A: "every day" is too strong, histograms show frequency of temperature ranges, not daily values. So A is wrong. Option B: If Minneapolis is the city with the lower temperature range (e.g., its daily highs are in 15 - 18, and the other city in 21+), then Minneapolis has the coldest daily high (since its maximum daily high is in 15 - 18, which is lower than the other city's minimum in 21+). Wait, but maybe the user's histogram (the one provided) has two histograms, one with 15 - 18 and another with 21 - 33+. So the city with 15 - 18 has a lower temperature range. So if Minneapolis is that city, then B is correct. But wait, the original options: Let's think again. The key is that histograms show the distribution of temperatures. If one city has a temperature range (daily highs) that is entirely lower than the other, then the city with the lower range has the coldest daily high. So if Minneapolis is in the 15 - 18 bin (and the other in 21+), then Minneapolis has the coldest daily high. Option A is wrong because "every day" can't be determined from a histogram (which is about frequency of ranges, not daily values). So B is correct? Wait, no, maybe I made a mistake. Wait, the problem says "these histograms" – maybe there are two histograms, one for each city. Suppose one histogram has a bar at 15 - 18, and the other at 21 - 33. Then the city with the 15 - 18 bar has daily highs in that range, and the other in 21+. So the city with 15 - 18 has the coldest daily high (since its maximum daily high is less than the minimum of the other city's daily highs). So if Minneapolis is that city, then B is correct. Option A is wrong because we can't say "every day" – histograms are about how many days had a certain temperature range, not day - by - day comparison. So the correct answer is B? Wait, no, maybe the user's original problem has a typo, but based on the given options:
Wait, let's re - analyze:
- Option A: "It was warmer in Minneapolis every day." Histograms show the frequency of temperature ranges, not individual daily temperatures. So we can't know if it was warmer every day. So A is incorrect.
- Option B: "Minneapolis had the coldest daily high temperature of these two cities." If one city's temperature range (daily highs) is in 15 - 18 and the other in 21 - 33, then the city with 15 - 18 has a lower maximum daily high (and lower minimum) than the other. So if Minneapolis is that city, then it has the coldest daily high (since its daily highs are in a low…
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B. Minneapolis had the coldest daily high temperature of these two cities.