Question

1. which point listed below does not belong to the graph of a line whose equation is -5x + 3y = -10?

you must show all of your work for this question to receive credit. please refer to the document linked in our canvas course in the course materials module for guidance on acceptable work
(1/5, -3)
(-1, -5)
(8, 10)

Explanation:

Step1: Substitute point (1/5, - 3)

Substitute $x=\frac{1}{5}$ and $y = - 3$ into $-5x + 3y$. We get $-5\times\frac{1}{5}+3\times(-3)=-1 - 9=-10$.

Step2: Substitute point (-1, -5)

Substitute $x=-1$ and $y = - 5$ into $-5x + 3y$. We have $-5\times(-1)+3\times(-5)=5 - 15=-10$.

Step3: Substitute point (8, 10)

Substitute $x = 8$ and $y = 10$ into $-5x+3y$. Then $-5\times8 + 3\times10=-40+30=-10$.

Answer:

There is no such point among the given options that does not belong to the graph of the line. If there was a mistake in the last - point's $y$ - value (assuming it was meant to be something else), based on the work above for the points presented, all the points $( \frac{1}{5},-3),(-1,-5),(8,10)$ satisfy the equation $-5x + 3y=-10$. If the last point was mis - typed, re - check the $y$ - value for the point $(8,y)$ and substitute again to find the non - belonging point.