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5 which savings plan can be modeled by $y = 50x + 25$? a start with $50…

Question

5 which savings plan can be modeled by $y = 50x + 25$?
a start with $50. save $25 each week.
b save $250 in 5 weeks for a total of $300.
c start with $25. the total saved after 5 weeks is $275.
d the total saved is $25 the first week and $50 the second week.

Explanation:

Step1: Identify slope-intercept form

The equation $y = 50x + 25$ follows the slope-intercept form $y=mx+b$, where $b$ is the initial amount, and $m$ is the weekly savings. Here, $b=25$, $m=50$.

Step2: Verify Option A

Option A: Initial amount $50$, weekly save $25$. This matches $y=25x+50$, not the given equation.

Step3: Verify Option B

Option B: Total after 5 weeks is $300$, with $250$ saved in 5 weeks. Initial amount would be $300-250=50$, weekly save $\frac{250}{5}=50$, matching $y=50x+50$, not the given equation.

Step4: Verify Option C

Option C: Initial amount $25$. For $x=5$ weeks, calculate total:
$y=50(5)+25=250+25=275$, which matches the claim. This aligns with the given equation.

Step5: Verify Option D

Option D: Week1 total $25$, week2 total $50$. Weekly save is $50-25=25$, initial amount $25$, matching $y=25x+25$, not the given equation.

Answer:

C. Start with $25. The total saved after 5 weeks is $275.