Question

in which scenario would the median be a more appropriate measure of central tendency due to skewed data? earnings from a weekend bake sale by five students: $30, $35, $37, $40, $42. earnings from a summer job of five students: $200, $220, $230, $240, $1,300. money earned from selling old textbooks: $5, $7, $8, $10, $18. weekly allowances of five students: $10, $12, $13, $15, $20.

Explanation:

To determine when the median is more appropriate, we check for skewed data (outliers). Let's analyze each scenario:

Step 1: Analyze Weekend Bake Sale Earnings

Data: $30, $35, $37, $40, $42.
These values are relatively close, no extreme outliers. Mean would also be appropriate.

Step 2: Analyze Summer Job Earnings

Data: $200, $220, $230, $240, $1,300.
Here, $1,300 is a large outlier (skews the data right). The median is less affected by outliers, so it's more appropriate here.

Step 3: Analyze Selling Old Textbooks Earnings

Data: $5, $7, $8, $10, $18.
Values are close, no extreme skew. Mean is reasonable.

Step 4: Analyze Weekly Allowances

Data: $10, $12, $13, $15, $20.
Values are close, no extreme skew. Mean is reasonable.

Answer:

Earnings from a summer job of five students: $200, $220, $230, $240, $1,300.