Question

which set of ordered pairs represents a function?
o {(2, -2), (1, 5), (-2, 2), (1, -3), (8, -1)}
o {(3, -1), (7, 1), (-6, -1), (9, 1), (2, -1)}
o {(6, 8), (5, 2), (-2, -5), (1, -3), (-2, 9)}
o {(-3, 1), (6, 3), (-3, 2), (-3, -3), (1, -1)}

Explanation:

Step1: Recall function definition

A function is a relation where each input (x - value) has exactly one output (y - value).

Step2: Check first set

In the set $\{(2, - 2),(1,5),(-2,2),(1, - 3),(8, - 1)\}$, the input $x = 1$ has two outputs $y = 5$ and $y=-3$, so it's not a function.

Step3: Check second set

In the set $\{(3, - 1),(7,1),(-6, - 1),(9,1),(2, - 1)\}$, each input has a unique output. So it is a function.

Step4: Check third set

In the set $\{(6,8),(5,2),(-2, - 5),(1, - 3),(-2,9)\}$, the input $x=-2$ has two outputs $y = - 5$ and $y = 9$, so it's not a function.

Step5: Check fourth set

In the set $\{(-3,1),(6,3),(-3,2),(-3, - 3),(1, - 1)\}$, the input $x=-3$ has three outputs $y = 1$, $y = 2$ and $y=-3$, so it's not a function.

Answer:

$\{(3, - 1),(7,1),(-6, - 1),(9,1),(2, - 1)\}$