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write the equation of a line that is parallel to (y = - 0.75x) and that…

Question

write the equation of a line that is parallel to (y = - 0.75x) and that passes through the point ((8,0)).

Explanation:

Step1: Determine the slope

Parallel lines have equal slopes. The slope of the line $y = - 0.75x$ is $m=-0.75=-\frac{3}{4}$. So the slope of the required line is also $m =-\frac{3}{4}$.

Step2: Use the point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)=(8,0)$ and $m =-\frac{3}{4}$. Substitute these values into the formula:
$y-0 =-\frac{3}{4}(x - 8)$.

Step3: Simplify the equation

$y=-\frac{3}{4}x+6$.

Answer:

$y =-\frac{3}{4}x + 6$