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write an equation of the line that passes through (7, 10) and is perpen…

Question

write an equation of the line that passes through (7, 10) and is perpendicular to the line $y = \frac{1}{2}x - 9$.
$y = \square$

Explanation:

Step1: Find perpendicular slope

The slope of $y=\frac{1}{2}x-9$ is $\frac{1}{2}$. Perpendicular slopes multiply to $-1$, so new slope $m = -2$.

Step2: Use point-slope form

Point-slope formula: $y - y_1 = m(x - x_1)$. Substitute $(7,10)$ and $m=-2$:
$y - 10 = -2(x - 7)$

Step3: Simplify to slope-intercept form

Expand and isolate $y$:
$y - 10 = -2x + 14$
$y = -2x + 14 + 10$
$y = -2x + 24$

Answer:

$y = -2x + 24$