Question

write the standard form of the equation of the circle described below. center (7, - 6), r = 3
the standard form of the equation of the circle is
(type an equation. simplify your answer.)

Explanation:

Step1: Recall circle - equation formula

The standard - form equation of a circle is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center of the circle and $r$ is the radius.

Step2: Identify values of $h$, $k$, and $r$

Given that the center is $(7,-6)$ and $r = 3$, so $h = 7$, $k=-6$, and $r = 3$.

Step3: Substitute values into the formula

Substitute $h = 7$, $k=-6$, and $r = 3$ into $(x - h)^2+(y - k)^2=r^2$. We get $(x - 7)^2+(y-(-6))^2=3^2$.

Step4: Simplify the equation

$(x - 7)^2+(y + 6)^2=9$.

Answer:

$(x - 7)^2+(y + 6)^2=9$