Question

y = -x - 1\
y = 2x - 7\
plot two lines by clicking the graph.\
click a line to delete it.

Explanation:

Step1: Find two points for \( y = -x - 1 \)

When \( x = 0 \), \( y = -0 - 1 = -1 \), so we have the point \( (0, -1) \).
When \( x = 2 \), \( y = -2 - 1 = -3 \), so we have the point \( (2, -3) \).

Step2: Find two points for \( y = 2x - 7 \)

When \( x = 0 \), \( y = 2(0) - 7 = -7 \), so we have the point \( (0, -7) \).
When \( x = 3 \), \( y = 2(3) - 7 = -1 \), so we have the point \( (3, -1) \).

To plot the lines:

• For \( y = -x - 1 \), plot the points \( (0, -1) \) and \( (2, -3) \), then draw a line through them.
• For \( y = 2x - 7 \), plot the points \( (0, -7) \) and \( (3, -1) \), then draw a line through them.

(Note: Since the task involves clicking on the graph to plot, the above steps help identify key points to plot for each line. The intersection point of these two lines (which can be found by solving the system \( -x - 1 = 2x - 7 \), giving \( x = 2 \), \( y = -3 \)) is \( (2, -3) \), which is consistent with the points found.)

Answer:

To plot \( y = -x - 1 \), use points like \( (0, -1) \) and \( (2, -3) \). To plot \( y = 2x - 7 \), use points like \( (0, -7) \) and \( (3, -1) \). Draw lines through these points on the graph.