Question

7 yd. 6 yd. b what is the perimeter? if necessary, round to the nearest tenth. yards

Explanation:

Step1: Find the base using Pythagorean theorem

Let the hypotenuse $c = 7$ yd and one - leg $a = 6$ yd. By the Pythagorean theorem $c^{2}=a^{2}+b^{2}$, so $b=\sqrt{c^{2}-a^{2}}$. Substituting the values, we have $b=\sqrt{7^{2}-6^{2}}=\sqrt{49 - 36}=\sqrt{13}\approx3.6$ yd.

Step2: Calculate the perimeter

The perimeter $P$ of a triangle is the sum of the lengths of its sides. So $P=7 + 6+\sqrt{13}\approx7 + 6+3.6 = 16.6$ yd.

Answer:

$16.6$