Question

you will have 3 attempts on this quiz. do not use any notes on your 1st attempt. you may use notes on your 2nd attempt. ask question(s) if needed prior to moving on to the 3rd attempt. question 9 9.1 pts in some cattle the genes for brown hair and for white hair are codominant. cattle with alleles for both brown and white hair, have both brown and white hairs. this condition gives the cattle a reddish color, and is referred to as roan. what is the probability, expressed as a percentage, of a roan cow and a roan bull having a white offspring? 25% 75% 50% 0%

Explanation:

Step1: Define alleles

Let \( B \) represent the allele for brown hair and \( W \) represent the allele for white hair. Since roan cattle have both brown and white hairs (codominant), their genotype is \( BW \).

Step2: Set up Punnett square

A roan cow (\( BW \)) and a roan bull (\( BW \)) will produce the following Punnett square:

	\( B \)	\( W \)
\( W \)	\( BW \)	\( WW \)

Step3: Determine genotypes

The possible genotypes of the offspring are \( BB \) (brown), \( BW \) (roan), \( BW \) (roan), and \( WW \) (white).

Step4: Calculate probability

There are 4 possible outcomes. The number of white offspring (genotype \( WW \)) is 1. The probability is \( \frac{1}{4} = 0.25 \), or 25% when expressed as a percentage.

Answer:

25% (corresponding to the option "25%")