Question

you have 2 coins: one penny and one nickel. consider the probability of flipping both coins in a cup and recording the combination as one outcome, with the outcome of the penny first and then the nickel. the sample space of the outcomes would be as follows: s = {hh, ht, th, tt} compute the classical probability of getting heads on at least one of the coins in one cup flip. enter as a decimal and round to 2 decimal places if necessary. answer: the p(at least one coin = h) = __________

Explanation:

Step1: Find the total number of outcomes

The sample - space $S=\{HH, HT, TH, TT\}$, so the total number of outcomes $n(S)=4$.

Step2: Find the number of favorable outcomes

The event of getting at least one head means the outcomes are $HH$, $HT$, $TH$. So the number of favorable outcomes $n(A) = 3$.

Step3: Calculate the probability

The classical probability formula is $P(A)=\frac{n(A)}{n(S)}$. Substituting the values, we get $P(A)=\frac{3}{4}=0.75$.

Answer:

$0.75$