Question

1. you have sampled a population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. using that 36%, calculate the following:

a. the frequency of the \a\ allele:
b. the frequency of the \a\ allele:
c. the frequency of the \aa\ genotype:
d. the frequency of the \aa\ genotype:
e. the frequency of the \aa\ genotype:

Explanation:

Step1: Calculate frequency of "a" allele

We know that the frequency of the homozygous recessive genotype (aa) is $q^{2}=0.36$. Taking the square - root of $q^{2}$ gives the frequency of the "a" allele. So, $q = \sqrt{0.36}=0.6$.

Step2: Calculate frequency of "A" allele

Using the Hardy - Weinberg equation $p + q=1$, where $p$ is the frequency of the "A" allele and $q$ is the frequency of the "a" allele. Since $q = 0.6$, then $p=1 - q=1 - 0.6 = 0.4$.

Step3: Calculate frequency of "AA" genotype

The frequency of the "AA" genotype is $p^{2}$. Substituting $p = 0.4$, we get $p^{2}=(0.4)^{2}=0.16$.

Step4: Calculate frequency of "Aa" genotype

The frequency of the "Aa" genotype is $2pq$. Substituting $p = 0.4$ and $q = 0.6$, we get $2\times0.4\times0.6 = 0.48$.

Step5: Frequency of "aa" genotype is given

The frequency of the "aa" genotype is given as $0.36$.

Answer:

a. $0.4$
b. $0.6$
c. $0.16$
d. $0.48$
e. $0.36$