Question

you will see a few examples of applications to practice with. your real test will have a test bank that will pull one question of any type.

the length of a rectangular garden is 9 feet longer than its width. if the gardens perimeter is 202 feet, what is the area of the garden in square feet?

Explanation:

Step1: Define variables for width/length

Let width = $w$, length = $w+9$

Step2: Use perimeter formula

Perimeter of rectangle: $P=2(l+w)$
Substitute values: $202=2((w+9)+w)$

Step3: Simplify and solve for $w$

$202=2(2w+9)$
$101=2w+9$
$2w=101-9=92$
$w=\frac{92}{2}=46$

Step4: Find length

Length = $46+9=55$

Step5: Calculate area

Area = $l\times w = 55\times46$

Answer:

2530 square feet