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you spin the spinner once. what is p(not 7)? $\frac{5}{6}$ $\frac{1}{3}…

Question

you spin the spinner once. what is p(not 7)? $\frac{5}{6}$ $\frac{1}{3}$ $\frac{1}{4}$ $\frac{4}{9}$

Explanation:

Step1: Find total number of outcomes

There are 6 sections on the spinner, so total number of outcomes $n = 6$.

Step2: Find number of non - 7 outcomes

The number of sections that are not 7 is 5.

Step3: Calculate probability

The probability formula is $P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P(\text{not }7)=\frac{5}{6}$.

Answer:

$\frac{5}{6}$