Question

if a 3,000 kg car is pulled with a force of 11,000 n to the right, causing it to accelerate at 3 m/s2, then what is the force of friction (ff) acting on the car?
_____ n
do not include units in your answer.
enter the answer

Explanation:

Step1: Apply Newton's second law

$F_{net}=ma$

Step2: Define net - force

$F_{net}=F - F_f$, where $F$ is the applied force and $F_f$ is the frictional force. So $ma=F - F_f$.

Step3: Rearrange for frictional force

$F_f=F - ma$

Step4: Substitute values

$m = 3000$ kg, $a=3$ m/s², $F = 11000$ N. Then $F_f=11000-3000\times3$.
$F_f=11000 - 9000$.

Answer:

2000