Question

(04.02 mc) write the equation of a line in standard form that has x - intercept (-p, 0) and y - intercept (0, -r). 〇 px - ry = -pr 〇 px - ry = pr 〇 rx + py = -pr 〇 rx + py = pr

Explanation:

Step1: Use intercept form of line

The intercept form of a line is $\frac{x}{a} + \frac{y}{b} = 1$, where $a$ is the x-intercept and $b$ is the y-intercept. Here, $a=-P$, $b=-R$.
Substitute values: $\frac{x}{-P} + \frac{y}{-R} = 1$

Step2: Eliminate denominators

Multiply every term by $-PR$ to clear fractions:
$(-PR)\cdot\frac{x}{-P} + (-PR)\cdot\frac{y}{-R} = (-PR)\cdot1$
Simplify each term: $Rx + Py = -PR$

Answer:

B. $Rx + Py = -PR$