Question

9:09 am mon oct 6 blackboard.ceriedu test information description instructions from the list of choices, select the one best answer. multiple attempts not allowed. this test can only be taken once force completion this test can be saved and resumed later. your answers are saved automatically. question completion status: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 << question 6 of 20 >> moving to another question will save this response. 5 points save answer question 6 (problem reference 5 - 1) a 60 kg cyclist turns a corner with a radius of 50 m at a speed of 20 m/s. what is the magnitude of the cyclists centripetal acceleration? 8.0 m/s² 2.5 m/s² 0.4 m/s² 9.8 m/s²

Explanation:

Step1: Recall centripetal - acceleration formula

The formula for centripetal acceleration is $a_c=\frac{v^{2}}{r}$, where $v$ is the speed and $r$ is the radius of the circular path.

Step2: Substitute given values

We are given that $v = 20\ m/s$ and $r=50\ m$. Substituting these values into the formula, we get $a_c=\frac{20^{2}}{50}$.

Step3: Calculate the result

$20^{2}=400$, so $a_c=\frac{400}{50}=8.0\ m/s^{2}$.

Answer:

$8.0\ m/s^{2}$