Question

1. a) 0n red b) 7n, right purple c) 28n, right green 10. a) 2n, right red b) 12n, right purple c) 2n, left blue 11. two students. student a kicks the ball with a force of 80n to the right. student b kicks the ball with a force of 45n to the left. calculate the net force. a) 45n, right brown b) 35n, right orange c) 40n, right yellow 12. three dogs are pulling on a stuffed animal. dog a pulls with a force of 150n to the north. dog b pulls with a force of 150n to the south. dog c (a much smaller dog) is pulling to the east with a force of 40n. which dog will win the toy? a) dog a red - orange b) dog b yellow c) dog c green

Explanation:

Step1: Define positive - direction

Let the right - hand direction be positive.

Step2: Calculate net force for question 9

The forces acting on the object in question 9 are $F_1=- 7N$ and $F_2=-7N$ (left - hand direction) and $F_3 = 14N$ (right - hand direction). The net force $F_{net}=F_1 + F_2+F_3=-7 - 7+14 = 0N$.

Step3: Calculate net force for question 10

The forces acting on the object in question 10 are $F_1=-3N$ and $F_2=-4N$ (left - hand direction) and $F_3 = 5N$ (right - hand direction). The net force $F_{net}=F_1 + F_2+F_3=-3-4 + 5=-2N$. The negative sign indicates the direction is to the left.

Step4: Calculate net force for question 11

Student A exerts a force $F_A = 45N$ to the right and student B exerts a force $F_B=-45N$ to the left. The net force $F_{net}=F_A+F_B=45+( - 45)=0N$.

Step5: Analyze forces for question 12

Dog A and Dog B are pulling in opposite directions (north - south) with equal forces of $150N$, so the net force in the north - south direction is $F_{NS}=150 - 150 = 0N$. Dog C is pulling with a force of $40N$ to the east. Since there is no force opposing Dog C in the east - west direction, Dog C will win the toy.

Answer:

1. A) 0N [red]
2. C) 2N, left [blue]
3. A) 0N [red]
4. C) Dog C [green]