Question

1. (-1, 3); y = -7x - 4\

y = 8x + 5

Explanation:

Step1: Substitute the point into the equations

We have the point \((-1, 3)\) and two equations \(y = -7x - 4\) and \(y = 8x + 5\). First, substitute \(x=-1\) and \(y = 3\) into the first equation \(y=-7x - 4\).
Left - hand side (LHS) is \(y = 3\), Right - hand side (RHS) is \(-7\times(-1)-4=7 - 4 = 3\). So LHS = RHS for the first equation.

Step2: Check the second equation

Now substitute \(x = -1\) and \(y = 3\) into the second equation \(y=8x + 5\).
LHS is \(y = 3\), RHS is \(8\times(-1)+5=-8 + 5=-3\). Since \(3
eq - 3\), the point \((-1,3)\) satisfies the equation \(y=-7x - 4\) but not \(y = 8x+5\).

Answer:

The point \((-1,3)\) satisfies the equation \(y=-7x - 4\) and does not satisfy the equation \(y = 8x + 5\). If the question is to check which equation the point \((-1,3)\) lies on, the answer is \(y=-7x - 4\).